Thread: Warhead data
View Single Post
  #81  
Old 02-17-2016, 11:25 AM
mmartin798 mmartin798 is offline
Registered User
 
Join Date: Feb 2014
Location: Michigan
Posts: 659
Default

Quote:
Originally Posted by ArmySGT. View Post
So, with a velocity.... we need a diameter for the e-factor formula.

Modern grenade? 1mm? or 0.5 mm? for a fragment.......?
Ok, density of steel = 8.05 g/cm^3

Mass of an M67 fragment = 0.1 g

Volume of an M67 fragment = 0.1/8.05 = .01242 cm^3

Volume of a cylinder is given by:
V= pi * r^2 * h
Assuming height equals diameter gives:
V = pi * r^2 * 2 * r
V = 2 * pi * r^3
Solving for r gives:
r = (V/(2*pi))^(1/3)
Doing the substitutions and doubling the radius to get the diameter and height we get 0.251 cm or 2.51 mm

If we assume a softer steel with a density of 7.75 g/cm^3, the diameter comes to 2.54 mm

Last edited by mmartin798; 02-17-2016 at 11:41 AM.
Reply With Quote