4th Economics 101

[mmartin798]

Sure. I just realized I quoted some wrong number for the meat anyway, so I will correct that here.

I will assume no exceptional attributes, so this is where we start:

Tech Level (TL): E
Population: 10
Volatile: 50%
Extrovert: 50%
Compassion: 50%
Discipline: 50%
Curious: 50%
Organization: 50%

The available labor pool is 2/3 of 50% of 10, or 3 people. At 2000 man-hours per year, we have 6000 hours available.

To feed 10 people, we need 3000kg of wheat and 500kg of meat.

At TL E, each hectare yields 1300kg of wheat per year and takes 80 hours per hectare to work and harvest. So we need 3000/1300, or 1.36 hectares of land to provide the people's wheat. This require 108.8 hours, so less than one farmer so far.

Let's assume they keep chickens, since they take up less space than beef. We assume they only eat 10% of the flock each year. So to get the 500kg of meat, we need 500/115 hectare of land, or 4.35 hectares for their coop and "grazing" area. They grow corn to feed the chickens. The amount of corn is 2.5*500/2 (the corn multiplier) or 625 kg wheat equivalents. But since only 10% of the flock is eaten, we need to multiply that by 10, giving 6250kg. Again, TL E produces 1300 kg/hectare, we need 6250/1300, or 4.8 hectares to grow the corn on. We add the two areas together, 4.35+4.80, to give 9.15 hectares. At TL E, each hectare takes 80 hours, so we need 9.15*80 or 732 man-hours per year for the chickens and their feed.

So to feed the settlement, we need to supply 841 man-hours, which is still one farmer. We now add the inputs for one person in the ag sector at TL E, which is 2000. The total man-hours to feed this settlement is 2841.

[mmartin798]

The biggest problem is the use of different units all the time. The calculations really need to be calculated in hours, but they keep quoting labor years. It really messes things up.

[ArmySGT.]

Originally Posted by mmartin798

The biggest problem is the use of different units all the time. The calculations really need to be calculated in hours, but they keep quoting labor years. It really messes things up.

The livestock table uses hectares for pasture on some animals and square meters for other animals. another area they should have stayed with one unit.

[ArmySGT.]

Originally Posted by mmartin798

So we need 3000/1300, or 1.36 hectares of land to provide the people's wheat. This require 108.8 hours, so less than one farmer so far.

3000/1300=2.307 ........ Wouldn't that be 2.3 Hectares... 80*2.3= 184 labor hours?

[mmartin798]

Originally Posted by ArmySGT.

3000/1300=2.307 ........ Wouldn't that be 2.3 Hectares... 80*2.3= 184 labor hours?

You are quite correct. So that gives us... 916 man-hours and we will need 2000 man-hours of inputs since that is still one farmer.

[ArmySGT.]

Originally Posted by mmartin798

They grow corn to feed the chickens. The amount of corn is 2.5*500/2 (the corn multiplier) or 625 kg wheat equivalents. But since only 10% of the flock is eaten, we need to multiply that by 10, giving 6250kg. Again, TL E produces 1300 kg/hectare, we need 6250/1300, or 4.8 hectares to grow the corn on. We add the two areas together, 4.35+4.80, to give 9.15 hectares. At TL E, each hectare takes 80 hours, so we need 9.15*80 or 732 man-hours per year for the chickens and their feed.

Shouldn't this be 2.5*500*2=2500 Kg of corn? 1300kg per hectare with x2 for corn = 2600kg produced for one hectare of corn. 2500 kg of corn for 10% of the flock?

[mmartin798]

Originally Posted by ArmySGT.

Shouldn't this be 2.5*500*2=2500 Kg of corn? 1300kg per hectare with x2 for corn = 2600kg produced for one hectare of corn. 2500 kg of corn for 10% of the flock?

No, this is another area where the text is confusing. Let me rephrase things to make it clearer. Just like explosives have an RE value where C4 is 1, so too does crop yield have a Yield Effectiveness (YE) value where wheat is 1. Replace crop multiplier with YE and the calculations are the same. 1 of wheat = 0.5 of corn = 100 of cocaine.

So if I need x hectares for 50kg of wheat, I need 0.5x hectares for 50kg of corn and 100x hectares for 50kg of cocaine. I hope that is clearer.

[ArmySGT.]

Originally Posted by mmartin798

No, this is another area where the text is confusing. Let me rephrase things to make it clearer. Just like explosives have an RE value where C4 is 1, so too does crop yield have a Yield Effectiveness (YE) value where wheat is 1. Replace crop multiplier with YE and the calculations are the same. 1 of wheat = 0.5 of corn = 100 of cocaine.

Hmmm ok..... What do you make of the multiplier? 1/12 for milk or 1/20 for poultry. Where does this fit in?

[mmartin798]

Originally Posted by ArmySGT.

Hmmm ok..... What do you make of the multiplier? 1/12 for milk or 1/20 for poultry. Where does this fit in?

Since they are roughly linear to the hectare yield, I think it was an attempt to simplify calculations that just adds to the noise. It is never used in any of the examples.

I think I figured out what the multiplier is in the livestock. It is kind of stupid. It lets you express the land the livestock uses to graze in terms of wheat. It is just way too confusing to use when we can calculate it from the other numbers easier.

[ArmySGT.]

Homestead #2
Tech D (Early Electric)
10 persons. 15-64=66% or 6.6 rounding up to 7 adults . Labor pool = 2/3 of 7= 4.62 rounding up to 5.

Tech level D Agriculture 11-25%, Mining / manufacturing/construction 25%, Distribution=20%, Other services 32%
5*0.25= 1.25, 5*0.20= 1, 5*0.32= 1.6
Five adults, One Farmer, One maker, One Trader, 2 Other.

Consume = 300kg wheat equivalents x 10 persons = 3000Kg

A Tech level D farmer produces 1300kg per hectare at 40 hours of work per hectare and can harvest 50 hectares per labor year (2000 labor hours).
3000kg/1300kg= 2.30 hectares of wheat produced for a labor hours of 92 hours.

The homestead requires 50Kg of meat and 150L of milk per person to adequately feed them.

50Kg*10= 500kg of meat and 1500L of milk.

The Homestead raises hogs for meats like hams and bacon. Hogs require 6kg of corn for each kilogram of pork at harvest. 6*500= 3000 kilos of corn….. only 10% of the herd can be harvested to keep the stock healthy though. 6*500 =3000/2*1300 = 1.2 hectares or 40*1.2= 48 labor hours * 10 (10% is consumed) 480 labor hours keeping hogs for meat.
2.3 hectares wheat and 1.2 hectares corn. 2.3+1.2= 3.5 hectares * 40 hours per hectare…. 140 labor hours plus 480 hours herding hogs for 620 labor hours per year farming the absolute minimum.

[ArmySGT.]

Extraction.... the Tech D homestead is producing natural gas.....

A natural gas well is tapped to produce fuel for the tractor, heating the home and out buildings and cooking meals. The gas well equipment, pumps, vacuums, refining, and pressure bottling is occupies one laborer (1 (laborer) x 5 (output) x 500 (material conversion factor)= 2500 and occupies 125,000M2 ((2500x100)/0.5=125000) This produces 2500kg of gas or 2500*35.3= 8825 cubic meters of natural gas.

8825 cubic meters of gas for one labor year.

To build the well took 1 (laborer)*6 (output) = 6 labor years (6*2000=12,000hrs) to get started and 1(laborer)*3(input)= 3 labor years (3*2000=6000 hours) annually in upkeep.

[mmartin798]

Originally Posted by ArmySGT.

Homestead #2
Tech D (Early Electric)
10 persons. 15-64=66% or 6.6 rounding up to 7 adults . Labor pool = 2/3 of 7= 4.62 rounding up to 5.

Tech level D Agriculture 11-25%, Mining / manufacturing/construction 25%, Distribution=20%, Other services 32%
5*0.25= 1.25, 5*0.20= 1, 5*0.32= 1.6
Five adults, One Farmer, One maker, One Trader, 2 Other.

Consume = 300kg wheat equivalents x 10 persons = 3000Kg

A Tech level D farmer produces 1300kg per hectare at 40 hours of work per hectare and can harvest 50 hectares per labor year (2000 labor hours).
3000kg/1300kg= 2.30 hectares of wheat produced for a labor hours of 92 hours.

The homestead requires 50Kg of meat and 150L of milk per person to adequately feed them.

50Kg*10= 500kg of meat and 1500L of milk.

The Homestead raises hogs for meats like hams and bacon. Hogs require 6kg of corn for each kilogram of pork at harvest. 6*500= 3000 kilos of corn….. only 10% of the herd can be harvested to keep the stock healthy though. 6*500 =3000/2*1300 = 1.2 hectares or 40*1.2= 48 labor hours * 10 (10% is consumed) 480 labor hours keeping hogs for meat.
2.3 hectares wheat and 1.2 hectares corn. 2.3+1.2= 3.5 hectares * 40 hours per hectare…. 140 labor hours plus 480 hours herding hogs for 620 labor hours per year farming the absolute minimum.

Your pork section is off. You are harvesting 500Kg of pork and leave an additional 4500Kg of pork alive. You need to feed them all and have land for them. I come up with 6*500*10=30000Kg of corn. That comes to 11.5 hectares, 462 man-hours. The land to graze the pork is 10*500/50 = 100 hectare, using 4000 man-hours. So the total land usage for just the pork is 111.5 hectare and requires 4462 man-hours a year. You need three people.

[ArmySGT.]

Originally Posted by mmartin798

Your pork section is off. You are harvesting 500Kg of pork and leave an additional 4500Kg of pork alive. You need to feed them all and have land for them. I come up with 6*500*10=30000Kg of corn. That comes to 11.5 hectares, 462 man-hours. The land to graze the pork is 10*500/50 = 100 hectare, using 4000 man-hours. So the total land usage for just the pork is 111.5 hectare and requires 4462 man-hours a year. You need three people.

500kg/0.10=5000kg of pork on the hoof to cull 10% yearly.

5000kg*6Kg of corn = 30000Kg of corn. Animal feed.

30000/1300=23.07 /2 = 11.5 hectares of corn. 11.5 * 40 = 460 labor hours.

10*500Kg/50kg per hectare = 100 hectares for the herd. 100 hectares x 40 (TL D) = 4000 labor hours. 4000 labor hours for herding + 460 hours growing grain requires 4460 labor hours to raise hogs. 4460/2000= 2.23 farmers rounding up to three.

[ArmySGT.]

So what if I change it to turkeys and geese? Meat, feathers, grease.

10*50kg per person... 500kg of meat.

2.5*500 = 1250 kg grain to feed *10 (only 10% of the flock is consumed)= 12500kg of corn consumed as animal feed. 12500/1300= 9.6 hectares /2 = 4.8 hectares cultivated as corn for animal feed. 4.8*40 (hectares * TL D labor hours) = 192 labor hours.

10*500/115=43.8 hectares of range land. 43.8*40 (hectares*TL D hours)=1739 labor hours

192+1739 = 1931 labor hours for 500 kg of poultry.