[mmartin798]

Sure. I just realized I quoted some wrong number for the meat anyway, so I will correct that here.

I will assume no exceptional attributes, so this is where we start:

Tech Level (TL): E
Population: 10
Volatile: 50%
Extrovert: 50%
Compassion: 50%
Discipline: 50%
Curious: 50%
Organization: 50%

The available labor pool is 2/3 of 50% of 10, or 3 people. At 2000 man-hours per year, we have 6000 hours available.

To feed 10 people, we need 3000kg of wheat and 500kg of meat.

At TL E, each hectare yields 1300kg of wheat per year and takes 80 hours per hectare to work and harvest. So we need 3000/1300, or 1.36 hectares of land to provide the people's wheat. This require 108.8 hours, so less than one farmer so far.

Let's assume they keep chickens, since they take up less space than beef. We assume they only eat 10% of the flock each year. So to get the 500kg of meat, we need 500/115 hectare of land, or 4.35 hectares for their coop and "grazing" area. They grow corn to feed the chickens. The amount of corn is 2.5*500/2 (the corn multiplier) or 625 kg wheat equivalents. But since only 10% of the flock is eaten, we need to multiply that by 10, giving 6250kg. Again, TL E produces 1300 kg/hectare, we need 6250/1300, or 4.8 hectares to grow the corn on. We add the two areas together, 4.35+4.80, to give 9.15 hectares. At TL E, each hectare takes 80 hours, so we need 9.15*80 or 732 man-hours per year for the chickens and their feed.

So to feed the settlement, we need to supply 841 man-hours, which is still one farmer. We now add the inputs for one person in the ag sector at TL E, which is 2000. The total man-hours to feed this settlement is 2841.