View Single Post
  #14  
Old 01-15-2016, 03:41 PM
ArmySGT.'s Avatar
ArmySGT. ArmySGT. is offline
Internet Intellectual
 
Join Date: Jun 2011
Location: Colorado
Posts: 2,412
Default

Quote:
Originally Posted by robj3 View Post
In overview:
Start with the settlement's Tech Level and population.
Calculate the size of the labor pool.
Distribute workers into agriculture, mining/mfg/construction, distribution, services.
Tech Level E.. Late Steam 1880s (pg 208)
Large Settlement 300 persons
Organization. 60% Leadership 30% Domain 3km2 per person 900 km2 (Pg 212)
Community trait None (pg214)
Labor pool: 47% under 15, 50% 15-64, 3% over 64%, 141, 150, 9 (pg 236)
Labor pool = 150 persons 15-64 / .66 = 99 Laborers
2000 labor hours per worker = 198, 000. Tech level E multiplier 4. 198000*4= 792,000 labor hours per year. (Pg 236)
Quote:
Originally Posted by robj3 View Post
Work through each sector.
Tech level E…. Farming 11-25, Miners, Makers, Builders 25, Deliverers 20, Services (32+. 99*0.25= 25, 99*0.25=25, 99*0.25 =25,99*0.32=32)
25+25+25+32= 104 (more workers needed than currently available…. Depending on farms output this may balance out with a reduction in agriculture workers. (Pg 237)
Quote:
Originally Posted by robj3 View Post
- how do I feed the population with the farmers available?
Agriculture Sector Tech level E. 80 hours per 25 Hectares per farmer (2khours per farmer per year)
Yield for Tech level E. 1300 kg wheat per hectare…. Supporting 4.3 persons base cost 6, input 1 (WTF is the explanation for base cost and input? Description in the rule book is lacking. Where do you use this? What are the modifiers per tech level?)
Can produce 900Km2 = 90,000 hectares (1 hectare = 10k meters2) One person requires 300kg equivalent per year. Village needs 90,000 Kg equivalent of wheat for 300 persons. 300*300=90000 (pg 237)
25 farmers with 25 hectares apiece per year equals 625 Hectares in farmland. (Pg 237) 812,500 kg of wheat per year possible; enough to feed 2708 persons annually. Outputs from other crops have their own modifiers (Pg237) 90,000kg wheat/1300Kg per hectare = 69 hectares = 2.76 or 3 farmers to produce the minimum wheat requirement at tech level E for 300 person.
Consumption = 50Kg meat and 150L milk per person per year.
Village need 300*50kg meat per person, per year, or 15,000 kg of meat produced. Village needs 300*150 liters of milk per person, per year, or 45,000 liters consumed as milk, cheese, butter, etc.
Milk = 180kg per hectare. 45000/180= 250 hectares to produce 45K liters with 2-10 hectares per animal, assuming 10 hectares for a cow and 2 hectares for a dairy goat.
This is where I quit again……. The table on (pg 238) has no explanation for the production, amounts per hectare, or why this spins off into man hours (to determine number of farmers) so one can eventually determine the kilograms per food type to feed the village.

So I can never get past agriculture to eventually get on to any of the other Economic sectors in determining whether a village is functioning or starving.
Quote:
Originally Posted by robj3 View Post
- how do I produce the raw materials the community needs?
Quote:
Originally Posted by robj3 View Post
- how is agricultural and factory product distributed?
Quote:
Originally Posted by robj3 View Post
- how are service workers distributed?
Quote:
Originally Posted by robj3 View Post
- how much energy is required to run everything?
Quote:
Originally Posted by robj3 View Post
- where does everyone live?
Reply With Quote